a square shaped park ABCD of side 100m has two equal rectangular flower beds each of size 10 × 5. what is the length of the boundary of the remaining park.
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Answer:
Option B is right
For Flower bed given that
Length(l)=10 m
Width(w)=5 m
∴ Perimeter of flower bed =2×(l+w)
=2×(10+5)m
=30 m.
There are two such flower beds.
For each bed, its one length and one breadth lie on boundary of the park.
So, perimeter of both flower bed lying on park=21(2×primeter of one bed)
=21(2×30)=30 m
Now, side of square ABCD=100 m
Therefore, perimeter of ABCD=4×100 m=400 m
So, perimeter of remaining area of park=perimeter of ABCD-perimeter of both flower bed lying on park
=400−30=370 m
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