Question

A square shaped park ABCD of side Om has Am-
two equal rectangular flower beds each of sive
10m x 5m (Fig. 6.5), length of the boundary of
the remaining park is
(A) 360m
(B) 400m
(C) 340m

(D) 460m
pls tell me answer fast .​

Answer 1

Step-by-step explanation:

For Flower bed given that

Length(l)=10 m

Width(w)=5 m

∴ Perimeter of flower bed =2×(l+w)

=2×(10+5)m

=30 m.

There are two such flower beds.

For each bed, its one length and one breadth lie on boundary of the park.

So, perimeter of both flower bed lying on park=21

(2×primeter of one bed)

= 21

(2×30)=30 m

Now, side of square ABCD=100 m

Therefore, perimeter of ABCD=4×100 m=400 m

So, perimeter of remaining area of park=perimeter of ABCD-perimeter of both flower bed lying on park

=400−30=370 m