CBSE BOARD XII, asked by vaishalisarate96, 24 days ago

A square sheet of cardboard with each side 'a' cm is to be used to make an open top box by cutting a small square of cardboard from each of the corners and bending up the sides. ​

Answers

Answered by Barani22
39

Explanation:

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Answered by KajalBarad
1

Answer - 432cm³

Given, A square sheet of cardboard with each side 'a' cm is to be used to make an open top box

To find ,

The maximum volume of the box.

Explanation -

Let the square's sides that are severed from each corner measure x cm.

The box's height will then be x cm and its base will have sides of 18–2x cm.

Consequently, box volume

V = (182x)(182x)x V = (18-2x)

²x V = 4x³ +324x - 72x² ... I

When we differentiate w.rt to x,

we obtain dV dx dV dx.

In the case of maximal volume,

12(x2 - 12x + 27) = 0;

x2 - 9x -3x+27; 0;

(x-9)(x-3); 0; and x = 9,

3 = 12x2 + 324 - 144x 12(x2 - 12x + 27)... (ii)

differentiating, we get

= 2x - 12 ...(iii)

At x = 9,

...V is minimum at x = 9 at x = 3

= +ve

...V is maximum at x = 3

... Maximum volume V = (18-6)(18-6) × 3

= 12 × 12 × 3 = 432cm³

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