Question

A square sheet of paper ABCD is so folded that B falls on the mid point of M of CD. Prove that the crease will divide BC in the ratio 5:3.

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

ook at these figures. (These are analytical figures. Don't take actual measurements.)

In right angled triangle B1CD, (Let the point dividing BC be D.), by Pythagorean Theorem,

(a-m)^2 = a^2+4m^2 /4

4a^2-8am+4m^2 = a^2+4m^2

8am=3a^2

3a=8m

m=3a/8 so a-m = 5a/8.

m/a-m = 3:5.

Thus, the crease divides BC in the ratio 3:5.

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