a square Side 2 centimetre is joined with a rectangle of length 15 cm and breadth 10 cm find the perimeter of the combinated shape
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48cm is the answer just join the figures and add all the lengths of the boundaries visible
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It is given that a square of side (a) 2 cm is joined with a rectangle of length (l) 15 cm and breadth (b) 10 cm.
So, we know that perimeter is the length of the boundary of a closed figure.
So, to get the perimeter here, we have to add all the sides (their length).
Let he perimeter be 'P' then.
ATQ:-
=>(a+a+a)+(l+l)+b=P
=>3a+2l+b=P
=>3×2+2×15+10=P
=>6+30+10=P
=>46 cm=P
So, the perimeter of the new figure formed=46 cm
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