Question

a square tile having 50 cm side is designed to wiyhstand a pressure of 200 n /m square. Find out if a force of 45 n can be applied on tile

Answer 1

As we know pressure = (force or load) / area
So area of tile=. 5² =.25m² (50cm =. 5m)
Force or load=200x.25=50n
So we can say that the tile can carry 45n force

Answer 2

Given,

Side of tile = 50cm

First  we  change  it  to Metre

We know,

1m = 100cm

100 cm = 1 m

1 cm = 1/100 m

50 cm = 50/100 m

50 cm = 1/2 m

50 cm = 0.5 m

Area  of  tile = (side)²

                     = 0.5 × 0.5

Area of  tile  = 0.25 m²

It is given that tile can carry a  pressure  of  200N/m². If  the  force applied  by this  pressure is  F,

F = Pressure × Area to tile

F = 200 × 0.25

F = 2 ×  25

F =  50 N

Hence, It  can  withstand any  force less  than 50 N