a square tile having a 50 cm side is designed to withstand a pressure of 200 N\m square
find out if a force of 45N can be applied on the side
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Given,
Side of tile = 50cm
First we change it to Metre
We know,
1m = 100cm
100 cm = 1 m
1 cm = 1/100 m
50 cm = 50/100 m
50 cm = 1/2 m
50 cm = 0.5 m
Area of tile = (side)²
= 0.5 × 0.5
Area of tile = 0.25 m²
It is given that tile can carry a pressure of 200N/m². If the force applied by this pressure is F,
F = Pressure × Area to tile
F = 200 × 0.25
F = 2 × 25
F = 50 N
Hence, It can withstand any force less than 50 N
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