Question

a square tile is having side of length 15cm how many such tiles would be required to cover the square floor of a bathroom of side 3m write easy formula also

Answer 1

Area of 1 tile =15×15=225cc Area of room= 300×300=90000cc(3m=300cm) No. Of tiles needed= 90000/225=400

Answer 2

SOLUTION :

The length of a square tile = 15 cm

The length of a square floor (of bathroom) = 3 m

                                                                       = (3 × 100) cm

                                                                       = 300 cm

[ ∴ as 1 m = 100 cm, to convert m into cm multiply 100 ]

To be found :-

The number of tiles that would required to cover the square floor of the bathroom

First,

find the area of the tile and area of the bathroom floor

Area of the tile of side 15 cm

= $\bf {(15)}^{2} }$ cm sq.     [ ∴ area of square = $\bf {(a)}^{2} }$ unit sq.  in which a is side of square ]

= 225 cm sq.

Area of the bathroom floor of side 300 cm

= $\bf {(300)}^{2} }$ cm sq.     [ ∴ area of square = $\bf {(a)}^{2} }$ unit sq.  in which a is side of square ]

= 90000 cm sq.

Now,

Number of tiles that would cover the area of the bathroom floor

= $\bf {\frac{Area \: of \: the \: bathroom \: floor}{Area \: of \: a \: tile} }$

= $\bf {\frac{90000}{225} }$

= $\boxed{\boxed{\bf{400}}}$

Hence,

400 number of tiles of side 15 cm each would be required to cover the square floor of a bathroom of side 3 m