Question

A square us inscribed in a circle of radius 7 √2
cm. find the total area of the portions of the circle
lying outside the square is​

Answer 1

Step-by-step explanation:

Diagonal of square = 2*Radius of Circle

$2 \times 7 \sqrt{2} = 14 \sqrt{2}$

Using Pythagoras Theorem,

$(14 \sqrt{2})^{2} = 2 \times side^{2}$

Thus, side = 14 cm

Area of circle portion outside the square

= Area of circle - Area of square

$= \pi(7 \sqrt{2})^{2} - {14}^{2}$

$= \pi \times 7 \times 7 \times 2 - 196$

$= 22 \times 7 \times 2 - 196$

$= 308 - 196$

$= 112 \: sqcm$