A square wire frame of side 10 cm is dipped in a liquid of
surface tension 28 x 10-3 N/m. On taking out, a membrane is
formed. What is the force acting on the surface of wire frames.
Answers
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Answer:
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Explanation:
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Answered by
13
Answer:
F = 2.24 × 10⁻² N
Explanation:
Given :
Side of square = 10 cm = 0.1 m
Surface tension = 29 × 10⁻³ N / m
We know :
The surface frame has two free surface.
= > Perimeter of square = 4 l
= > Total length of the frame = 4 l
We have expression for surface tension .
Surface tension = Force / Length
= > F = S × L
= > F = 8 × 0.1 × 28 × 10⁻³ N
= > F = 224 × 10⁻⁴ N
= > F = 2.24 × 10⁻² N
Therefore we get required answer.
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