a square wire of each side l carrier I the magnetic field at the mid-point at the midpoint op the square is
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The magnetic field at the midpoint of the square is 8√2μ₀i/4πl
Given-
- Side of the square wire = l
- Current in the wire = i
We know that magnetic field due to conductor subtending angles θ₁ and θ₂ is
B = μ₀i/4πR ( sin θ₂ - sin θ₁)
Here R is the length from the mid point. So R = L/2
Here θ = 45°
By substituting the values magnetic field due to one side is-
B = μ₀i/4πL/2 [ 1/√2 - (-1/√2)]
B = 2√2 μ₀i/4πL
B due to four sides
B = 4 × 2√2 μ₀i/4πL
B = 8√2μ₀i/4πl
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