Question

A squirrel runs at a speed of 9.9m/swith 25j of kinetic energy what is it mass

Answer 1

Answer:

Given:

Velocity of squirrel = 9.9 m/s

Kinetic energy = 25 J

To find:

Mass of squirrel

Formulas used:

KE = ½ mv²,

m is mass, v is velocity , KE is Kinetic energy

Calculation:

KE = ½ mv²

=> 25 = ½ m (9.9)²

=> 50 = m (9.9)²

=> m = 50/(98.01)

=> m = 0.51 kg.

Mass of squirrel is 0.51 kg.

Answer 2

${ \huge \bf { \mid{ \overline{ \underline{Question}}} \mid}}$

A squirrel runs at a speed of 9.9m/s With 25J of kinetic energy what is it mass?

$\huge{\bold{\underline{\underline{Answer}}}}$

$\huge{\bold{\underline{Given:-}}}$

• Speed of the Squirrel (v) = 9.9 m/s.
• Kinetic energy (K.E) = 25 Joules.

$\huge{\bold{\underline{Explanation:-}}}$

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Kinetic energy (K.E):-

• Kinetic energy is a Type of Mechanical energy .
• Kinetic energy is the energy possessed by the body due to virtue of its motion.
• It has units:- Joules (S.I units) & Ergs (C.G.S units)
• For a Body which is at rest the Kinetic energy will be Zero .

$\rule{300}{1.5}$

$\rule{300}{1.5}$

From Kinetic energy Derivation,

$\large{\boxed{\tt K.E = \dfrac{1}{2}mv^2}}$

Substituting the values,

$\large{\tt \leadsto 25 = \dfrac{1}{2} \times m \times (9.9)^2}$

$\large{\tt \leadsto 25 \times 2 = m \times (9.9)^2}$

$\large{\tt \leadsto 50 = m \times (9.9)^2}$

$\large{\tt \leadsto 50 = m \times 98.01}$

$\large{\tt \leadsto m = \dfrac{50}{98.01}}$

$\large{\tt \leadsto m = 0.51 \: Kg}$

As we know,

1Kg = 1000 grams

$\large{\tt \leadsto m = 0.51 \times 1000 \: g}$

$\large{\tt \leadsto m = 0.51 \times 1000}$

$\huge{\boxed{\boxed{\tt m = 510 \: grams}}}$

So, the Mass of the Squirrel is 0.51 Kg (or) 510 grams.

$\rule{300}{1.5}$