Question

A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.43 m/s² , what is the radius of the circle?

Answer 1

Answer:

centripetal acceleration is velocity square by radius

.43=.51*.51/r

r=.604 m

Answer 2

Answer:

0.6m

Explanation:

See the Attachment For explanation and solution.

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