Math, asked by roystar1444, 5 hours ago

a st line in parallel to the y= √3x Passes through a (2, 3) and cute line ax+4y-27 = 0 at P the find lingt of pq

Answers

Answered by aqsakhan0109
0

Answer:

Slope of line=m=tan6π=31

and passes through Q(3,2)

⇒Equation of line:

⇒y−2=31(x−3)

⇒y3−23=x−3

⇒y3−x=3

Other line3x−4y=−8

∴Point of intersection:

3x−4y=−8

−x+3y=3−x3

⇒−3x+3y=3

−y=−5

⇒y=5

3x=4y−8

⇒3x=12

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