Math, asked by chaqnation, 7 months ago

A stadium has 10,000 seats split into box seats lower deck seats and upper deck seats . Box seats sell for $10, lower deck seats ell for $8, upper deck seat sell for 5. When the stadium sells out, the revenue is $67,380. The stadium has 4 times as many upper deck seats as box seats. How many of each seat are in the stadium ( I need the work pls put it in your answer)

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Answered by Anonymous
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→ A stadium has 10,000 seats split into box seats lower deck seats and upper deck seats . Box seats sell for $10, lower deck seats ell for $8, upper deck seat sell for 5. When the stadium sells out, the revenue is $67,380. The stadium has 4 times as many upper deck seats as box seats. How many of each seat are in the stadium ?

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→ Let

→ x = the number of box seats

→ y = the number of lower-deck seats

→ z = the number of upper-deck seats

→ A stadium has 10,000 seats :

→ x + y + z = 10000

→ When all the seats for a game are sold, the total revenue is $70,000 :

→ 10x + 8y + 5z = 70000

→ The stadium has 4 times as many upper-deck seats as box seats :

→ z = 4x

→ We have the following system of equations :

→ x + y + z = 10000

→ 10x + 8y + 5z = 70000

→ z = 4x

▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀

→ x = 1,000 box seats

→ y = 5,000 lower-seats

→ z = 4,000 upper-seats

→ There are 5,000 lower-deck seats in the stadium.

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