A stair case contains ten steps each 10cm high and 20cm wide. The minimum horizontal velocity with which the ball has to be rolled off the upper most step, so as to hit directly the edge of the lowest step is (approximately) _m/s
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Answers
Answer:i hope it was helpful
Explanation:
To hit directly the lowest plane the ball has to cross the point B.
From A to B, the ball has to travel to horizontal distance equal 40cm=40m
and vertical distance of 20cm=0.2m.
Let the time taken to reach point be t.u=0m/s
h=0.2m
from the equation,h=ut+1/2gt
2
we get,
0.2=0+1/2x9.8t
2
t
2
=0.4/9.8
t
2
=0.04
t=0.2
Let v be the horizontal velocity of ball than the horizontal distance travelled by the ball=0.2v
in order to clear the point B it must be equal to 0.40.
2v=0.4
v=2m/s
∴So minimum velocity required to to hit the lowest floor is 2m/s.
Hence,
option (A) is correct answer.
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SIMILAR QUESTIONS
star-struck
Answer:
4.2 m/s
Explanation:
u√2h/g=R
u^2 2h/g=200^2
u^2 *2*10/10=40000
u^2=20000
u=100√2
u=141.4
u=1.4 m/s
v=u*t
v=1.4*3
v=4.2