Question

A stake of 50 identical cubical blocks each of mass 20 kg and volume 0.125 m3 are placed over one another over a horizontal floor. The total pressure exerted on the floor by them is [Take g = 10 m/s2]

Answer 1

Dear Student,

● Answer -

P = 40000 Pa

◆ Explaination -

Side length of cube is calculated as -

l = ∛V

l = ∛0.125

l = 0.5 m

Area of contact between cubes and floor is -

A = l²

A = 0.5²

A = 0.25 m²

Total force exerted by all the cubes is -

F = M × a

F = 50 × m × g

F = 50 × 20 × 10

F = 10000 N

Pressure exerted by cubes on the floor is -

P = F/A

P = 10000 / 0.25

P = 40000 Pa

Therefore, 40000 Pa pressure is exerted by the cubes on the floor.

Best luck dear...