A standard capacitor of capacitance 0.1 mewF is charged by a potential difference of 2 volts. It is then discharged through a ballistic galvanometer which gives a linear throw of 20cm on a scale at a distance of 1 Metre from the mirror of the B.G. calculate the charge sensitiveness of the galvanometer.
Answers
Answered by
0
Answer:
We know that for discharging of capacitor, where t is the time of discharge, Q=Q
o
e
(
RC
−t
)
Where Q
o
is the initial charge in the capacitor. As we know, Q=CV.
So, CV=CV
o
e
(
RC
−t
)
According to question, V=
2
V
o
.
Therefore,
2
V
o
=V
o
e
RC
−t
=>
2
1
=e
RC
−t
=>log0.5=
RC
−t
=>−0.301=
10×10
6
×0.1×10
−6
−t
=>−t=−0.301×(10×0.1)
=>t=0.301s
Similar questions