Physics, asked by shivakiranshenoy, 9 months ago

A standing wave is formed by the superposition of two waves travelling in opposite directions. The transverse
displacement is given by: yx,t=0.5sin
-x)cos 200mt) What is the speed of the travelling wave moving in
the positive x direction? (x and t are in meter and second respectively)
1) 160 m/s
2) 90 m/s
3) 180 m/s
4) 120 m/s​

Answers

Answered by abhi178
3

answer : option (1) 160 m/s

it is given that a standing wave is formed by the superposition of two waves travelling in opposite directions.

the displacement wave is given by, y(x, t) = 0.5sin(5π/4 x)cos(200πt/

we have to find the speed of the travelling wave.

we know, if two waves y₁ = Asin(ωt + kx) and y₂ = Asin(ωt - kx)

then supposition of these two waves , y = y₁+ y₂

= Asin(ωt + kx) + Asin(ωt - kx)

= 2Asin(ωt)cos(kx)

we also know, speed of travelling wave is given as v = ω/k

given equation is y = 0.5sin(5π/4 x)cos(200π t)

here ω = 200π , k = 5π/4

so, speed of travelling wave, v = (200π)/(5π/4)

Answered by Anonymous
2

Answer:

the displacement wave is given by, y(x, t) = 0.5sin(5π/4 x)cos(200πt/

we have to find the speed of the travelling wave.

we know, if two waves y₁ = Asin(ωt + kx) and y₂ = Asin(ωt - kx)

then supposition of these two waves , y = y₁+ y₂

= Asin(ωt + kx) + Asin(ωt - kx)

= 2Asin(ωt)cos(kx)

we also know, speed of travelling wave is given as v = ω/k

given equation is y = 0.5sin(5π/4 x)cos(200π t)

here ω = 200π , k = 5π/4

so, speed of travelling wave, v = (200π)/(5π/4)

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