Question

A standing wave propagating with velocity 300 m/s in an open pipe of length
4 m has four nodes. The frequency of the wave is
​

Answer 1

Answer:

v=300m/s

There are 4 nodes

⇒4(

2

λ

)=L=4

⇒λ=2m

v=fλ⇒f=

λ

v

⇒f=

2

300

=150Hz