A star is located a light year away from us.what is its distance in parsec .what is the parallax shown by this star when viewed from to locations 3×10^11m
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Hey.
Here is the answer.
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Distance of the star from us = 1 ly
1 light year is the distance travelled by light in one year.
So, 1 light year = Speed of light × 1 year
= 3 × 10^8 × 365 × 24 × 60 × 60
= 94608 × 10^11 m
∵ 1 parsec = 3.08 × 10^16 m
∴ 1 ly = 94608 × 10^11 / 3.08×10^16 parsec
= 0.30716883 parsec
_____________________________
Now, Using the relation,
θ = d / D
where,
Star is viewed from , d = 3 × 10^11 m
Distance of the star from the earth,
D = 94608 × 10^11 m
∴ θ = 3 × 10^11 / 94608 × 10^11 rad
= 3.17 × 10^-6 rad
But, 1 sec = 4.85 × 10^–6 rad
∴ 3.17 × 10^-6 rad = 3.17 × 10^-6 / 4.85 × 10^-6 sec
= 0.653 sec
Hence, the parallax shown by the star is of 0.653 sec when viewed from the given distance.
_______________________________
Thanks.
Here is the answer.
______________________________
Distance of the star from us = 1 ly
1 light year is the distance travelled by light in one year.
So, 1 light year = Speed of light × 1 year
= 3 × 10^8 × 365 × 24 × 60 × 60
= 94608 × 10^11 m
∵ 1 parsec = 3.08 × 10^16 m
∴ 1 ly = 94608 × 10^11 / 3.08×10^16 parsec
= 0.30716883 parsec
_____________________________
Now, Using the relation,
θ = d / D
where,
Star is viewed from , d = 3 × 10^11 m
Distance of the star from the earth,
D = 94608 × 10^11 m
∴ θ = 3 × 10^11 / 94608 × 10^11 rad
= 3.17 × 10^-6 rad
But, 1 sec = 4.85 × 10^–6 rad
∴ 3.17 × 10^-6 rad = 3.17 × 10^-6 / 4.85 × 10^-6 sec
= 0.653 sec
Hence, the parallax shown by the star is of 0.653 sec when viewed from the given distance.
_______________________________
Thanks.
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