Math, asked by popmeupuper, 9 months ago

A started from point P and went 2 km East; he
turned right and covered 3 km. At the end of 3 km,
his bicycle got punctured. He left it with the
mechanic and turned right and went 1 km. Then he
turned left and went 1 km and finally he turned
right and after walking 1 km, reached his destination.

How far is A's destination from P (shortest
distance in km)?
(A) 32 +22
(B) 42 +32
(C) 42 +22
(D) 4​

Answers

Answered by satvikshyam9gmailcom
0

Answer:

A 42 + 32

please mark me on brainly I follow you If you marks

Answered by supreethacmsl
2

Answer:

8 km

Step-by-step explanation:

Let us draw a picture/map of A's trip.

A

A starts from P and goes 2km east.

        2 km

A - - - - - - - - -

Then he turned right and covered 3km.

        2 km

A - - - - - - - - -

                    |

                    |        3km

                    |

                    |

Since his bicycle got punctured at the end of 3km, he left it with a mechanic and turned right and went on for 1km.

        2 km

A - - - - - - - - -

                    |

                    |        3km

                    |

                    |

               - - -

               1km

Then he turned left and went for 1km again.

        2 km

A - - - - - - - - -

                    |

                    |        3km

                    |

                    |

             - - - -

            |  1km

   1km  |

            |

He took a right and walked for 1km to reach his destination.

        2 km

A - - - - - - - - -

                    |

                    |        3km

                    |

                    |

             - - - -

            |  1km

   1km  |

            |

 - - - -

  1km

Now the question is how far the destination is from P,

= 2+3+1+1+1  = 8km

(#SPJ2)

Similar questions