A starts 3 hours after B who rides 12 km an hour and overtakes him after 5 hours at what rate is A is travelling
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Step-by-step explanation:
Let A travel at a speed of X km/hr
Speed of B = 12km/hr.
So distance covered in 3hrs = 36km
B is 36km ahead of A
Since both move in same direction: relative speed = (12-X)km/hr.
T = 5hrs given
D = SxT
36 = (12-X) x 5
36 = 60 - 5X
5X = 24
X = 24/5 = 4.8Km/hr
I'm sure this is not the right answer but I tried.
Please let me know if someone can give a proper solution.
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