(a) State a condition under which a body moves in such a way that the magnitude of its average velocity is equal to its average speed.
(b) A train starting from the rest moves with a uniform acceleration of 0.2 m/ s2 for five minutes. Calculate the final velocity acquired and the distance travelled in this time.
CBSE Class IX Science SA 2 (3 Marks)
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Answered by
29
(a) When a body moves along a straight line the
magnitude of its average velocity is equal to its average speed.
(b) Acceleration a = 0.2 m/s²,
Initial velocity u = 0, Time t = 5 minutes = 300 s
Final Velocity v = ?
a= (v — u)/t
0.2 = v / 300
Distance = speed x time
= 60 x 300
= 18000 m
=18 km
Answered by
11
a) a body falling freely under the action of gravitational force
b) velocity = acceleration × time
=> v= 0.2× 5 × 60 ( time in seconds )
=> v= 60 m/sec
distance = velocity × time
d= 60×300= 18000 mts
b) velocity = acceleration × time
=> v= 0.2× 5 × 60 ( time in seconds )
=> v= 60 m/sec
distance = velocity × time
d= 60×300= 18000 mts
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