Question

(a)state Gay-Lussac's Law of combining volumes,

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Answer 1

Answer:

Gay-Lussac's Law states that at constant volume for a fixed amount of gas, the pressure is directly proportional to its temperature in Kelvin. 

USE OF GAY LUSSAC'S LAW :

Q. Find the temperature in Celsius needed to change the pressure of 10.0 liters of a gas that has a pressure of 97.0 kPa at 25oC to standard pressure. Standard pressure is 101.325 kPa.

Sol : First, we have to convert 25oC to Kelvin (273+25=298K)

From Gay Lussac's law, we know that

           P∝T ( at constant volume )

          T1P1=T2P2 ............. (1)

Here, P1=97.0 kPa

          T1=298 K

          P2=101.325 kPa

          T2=?

Putting the above values in equation (1), we will get, 

          29897.0=T2101.325

          T2=97.0101.325×298

          T2=311.3K

In order to get temperature in celsius, we will have to subtract T2 by 273,               

          T2=(311.3−273)oC    

          

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Answer 2

Answer:

Gay-Lussac's law states that the pressure of a given mass of gas varies directly with the absolute temperature of the gas, when the volume is kept constant.

This formula can be expressed as follows:

(P1/T1) = (P2/T2) Where: P1 is the initial pressure. P2 is final Pressure. T1 is initial temp. T2 is final Temp....

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