Question

(a) State how is the distance travelled in any
part determing from this graph.
(6) Compare the distance travelled in part be
with the distance travelled in part AB.​

Answer 1

Cause the body started from origin .

Intial velocity (u)=0.

We use the formula:
v = u + at

Then we get acceleration (a)

Answer 2

a) First of all, we should know that

distance/ displacement=velocity/speed * time

In a velocity time graph,

Distance travelled is the area under graph

Look at the above image

To find the distance in part AB we should find the area of triangle ABE

distance in part AB=1/2bh

=1/2*AE*BE

To find the distance in part BC we should find the area of rectangle BCFE

distance in part BC=lb

=EF*FC

=(AF-AE)*FC

To find the distance in part CD we should find the area of triangle FCD

distance in part CD=1/2bh

=1/2*FD*FC

=1/2*(AD-AF)*FC

6)

There isnt any value in the graph....

Follow the above method , find the distance and compare them.

Hope it helps.....

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