Question

(a) state the law of momentum. (b) a mass of 200 kg is accelerated uniformly from a velocity of 10 m s-¹ to 16m s-¹ in 12 second. calculate the initial and final momentum of the object and the force that brings about this change

Answer 1

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(a)

The law of momentum states that ," The rate of the change of the momentum of a given body is directly proportional to the force due to the object ."

According to the law , F ∝ mv/t

=> F ∝ ma

=> F = kma ,where k = proportionality constant.

when , F =1N , a = 1m/s² and m= 1kg

then k=1

Hence, F = ma

(b)

Given Data :

Mass of the object ,m = 200kg

Rate of Change in velocity , a = [ v(2) - v(1) ]/t  = (16 - 10)/12 = 0.5m/s²

Formula :

F = ma

Substitution and simplification :

=> F = 200 * 0.5

=> F = 100 N

Hence , force exerted by the object is 100 N.

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