Question

a) State the relation between potential difference, work done and charge moved.
b) Calculate the work done in moving a charge of 4 coulombs from a point at 220 volts to another point at 230 volts.

Answer 1

If potential difference is taken as V, work done W and the charge moved as Q then the relationship is :

V = W/Q

b) We know by the above that V = W/Q
So, the needed potential difference = 230 - 220 = 10 V
Charge = 4 C
10 = W/4
W = 40 J

So the work done is 40 J

Hope This Helps You!

Answer 2

when a charge (q) move in and potential difference(∆V) so work done is given as

work done = charge × potential difference


=) W = q×∆V -----------(1)


equation (1) is the required relation between work done, potential difference and change moved.

Now according to question.

Given that:-

charge (q) = 4 C

potential difference(∆V) =( 230 - 220)

= 10 volt

so work done (W) = q× ∆V

= 4 ×10 = 40 joule


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Hope it will help u