Question

A stationary body of mass 3 kg explodes into three equal pieces. Two of the pieces fly off at right angles to each other, one with a velocity m/s and the other with a velocity m/s. If the explosion takes place in 10-5 s, the average force acting on the third piece in newton is

Answer 1

$\mathfrak{The\:Answer\:is}$

Force= rate of change of momentum by momentum conservation

1(2i^)+1(3j^)+1(v¯)=0

Δp=−[2i^+3j^]

F=ΔpΔt

=−[2i^+3j^]×105N

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