Question

A stationary body of mass 'm' explodes into three paths having mass in the ratio 3:3:1,its two fraction having equal masses moving at right angle to each other with velocity of 15m/s.what is the velocity of the third body?

Answer 1

Answer:

7√2

Explanation:

to use total conservation of momentum.

Finding the resultant:

p1=p2=3a×15

√(p1+p2) (vector addition)

=7√2a

now the resultant should be equal to the momentum of the other particle for total momentum to be zero.

hence v=7√2a/a

v=7√2