Question

A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of θ, where θ is the angle by which it has rotated, is given as kθ². If its moment of inertia is I then the angular acceleration of the disc is:
(A) (k/I)θ²
(B) (k/2I)θ
(C) (k/4I)θ
(D) (2k/I)θ

Answer 1

Answer:

A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of θ, where θ is the angle by which it has rotated, is given as kθ². If its moment of inertia is I then the angular acceleration of the disc is:

OPTION:;

(D) (2k/l)0