Question

A stationary meson decays in 2.2×10-8 sec .What will be the length of path if it is moving towards the earth with velocity 0.99c.

Answer 1

Given that,

Time $t= 2.2\times10^{-8}\ sec$

Velocity v= 0.99c

We need to calculate the length of path

Using formula of time

$t=\dfrac{l}{v}$

$l=v\times t$

Where, t = time

v = velocity

Put the value into the formula

$l=2.2\times10^{-8}\times0.99\times3\times10^{8}$

$l=6.534\ m$

Hence, The length of path is 6.534 m.