A stationary meson decays in 2.2×10-8 sec .What will be the length of path if it is moving towards the earth with velocity 0.99c. IN frame of reference fixed on the meson, what distance will earth travel before the meson decay.
Answers
Answer:It follows from Eq. (5) that β = 0.866 when ∆t = 2∆t
0
.
Eq. (4) indicates that the time interval ∆t measured by observers at rest in S is larger than the time interval
∆t
0 measured by an observer at rest with respect to the clock. That is, “moving clocks run slow”.
It is important to note that Eq. (4) relates clock readings on a single clock in S
0 with clock readings on two
separate clocks in S.
”Moving clocks run slow” is illustrated by the LIght Pulse Clock. For this clock, a light pulse is directed
along the positive y
0 axis and reflected back to its starting point. The traversal time is recorded as ∆t
0
. In S,
the clock moves along the positive x axis with speed v. A stationary observer records the time the light pulse
starts and a second stationary observer, farther to the right along the x axis, records the time when the light
pulse returns to its starting point. This traversal time is recorded as ∆t. Because of the sideways motion, the
light pulse travels farther in S than in S
0
. Since the speed of light is the same in both frames, it follows that
the ∆t is larger than ∆t
0
. The moving clock runs slow.