Physics, asked by sirgauravGaurab8404, 1 year ago

A stationary particle explodes into two particles of masses m1 and m2 which move in opposite directions with velocity v1 and v2 the ratio of the kinetic energy is given by key to is

Answers

Answered by Shaizakincsem
193

Thank you for asking this question. Here is your answer:

First of all we will solve this equation.

E₁/E₂ = 1/2 m₁v₁²/ 1/2m₂v₂²

= p²₁/2m₁/ P²₂/ 2m₂

= m₂/m₁

If there is any confusion please leave a comment below..


harshit636: how momentum of both body will be same?
kalpanachandar: It is given in the question that we have to consider both the masses to have same momentum. It is not an assumption..
Answered by Anonymous
156

The final momentum after explosion is equal to the initial momentum(from the law of conservation of energy).

Thus, m₁v₁ + m₂v₂ = (m₁+m₂)V

As initially the particle was static, V = 0 and as v₁ and v₂ is opposite in direction,

m₁v₁ - m₂v₂ = 0

or, m₁v₁ = m₂v₂

or, (m₁v₁)² = (m₂v₂)²

or, (1/2)m₁²v₁² = (1/2)m₂²v₂²

or, E₁.m₁ = E₂.m₂

or, E₁ / E₂ = m₂ / m₁



mullaanis22: In 4 step how ½ came???? Pls let me know as soon as possible
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