Question

a stationary shell explodes into two fragments having masses in the ratio 1 is to 2 the heavier fragment attains kinetic energy of hundred J. Kinetic energy released in explosion..​

Answer 1

Answer: 300J

Explanation:Dear student,

Let mass of pieces are m1=m and m2=2m

Applying conservation of momentum.

m1v1=m2v2

⇒mv1=2mv2

⇒v1=2v2

Now,  

⇒1/2m2(v2)2=100

⇒1/2×2m×(v1/2)2=100

⇒1/2m1(v1)2=100×12×4=200 J

Total KE = 300 J

Regards

Answer 2

Answer:

300J.

Explanation:

Since, from the question we know that the masses are in the ration 1:2 hence we can let the mass of pieces be m and 2m respectively.

So, now applying the momentum conservation theorem we get that.

m1v1=m2v2

mv1=(2m)v2

So, the value of velocity v1 will be =2v2.

Now,

Since we know that kinetic energy of heavier particle is 1/2m2(v2)2=100 J.

So, for the lighter particle it will be 1/2×2m×(v1/2)2=100

1/2m1(v1)2=100×12×4=200 J.

Total kinetic energy will be found to be 200+100=300 J.