Question

A stationary shell explodes into two fragments having masses in the ratio 1:2 thr heavier fragment attain kinectic energy of 100J . The kinectic energy rekeased in explosion is

Answer 1

Answer:

The kinetic energy released on explosion is 300 Joule

Explanation:

Let the mass of one fragment is m

Then the mass of the other fragment will be 2m

2m mass fragment has a kinetic energy of 100 J

Therefore,

$\frac{1}{2}\times 2mv^2=100$

$\implies mv^2=100$

$\implies v=\sqrt{\frac{100}{m}}$

If the velocity of mass m fragment is v' then

From conservation of linear momentum

$0=2m\timesv-m\timesv'$

$\0=2m\timesv-m\timesv'$

$\implies v'=2v$

Therefore, total Kinetic Energy of the system

$=\frac{1}{2}2mv^2+\frac{1}{2}2mv'^2$

$=100+\frac{1}{2}m(2v)^2$

$=100+\frac{1}{2}m(2v)^2$

$=100+\frac{1}{2}m(2\sqrt{\frac{100}{m}})^2$

$=100+\frac{1}{2}m\times4\times\frac{100}{m}$

$=100+2\times 100$

$=100+200$ J

$=300$ J

Therefore, the kinetic energy released on explosion is 300 J

Answer 2

Answer:

The kinetic energy released on explosion is 300 Joule

Explanation:

Let the mass of one fragment is m

Then the mass of the other fragment will be 2m

2m mass fragment has a kinetic energy of 100 J

Therefore,

If the velocity of mass m fragment is v' then

From conservation of linear momentum

Therefore, total Kinetic Energy of the system

J

J

Therefore, the kinetic energy released on explosion is 300 J

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Explanation: