Question

a stationary shell explodes into two fragments having masses in the ratio of 1:2.The heavier fragment attains a kinetic energy of 100J.The kinetic energy released in the explosion is​

Answer 1

Answer:

Let mass of pieces are m

1

=m and m

2

=2m

Applying conservation of momentum,

m

1

v

1

=m

2

v

2

⟹mv

1

=2mv

2

⟹v

1

=2v

2

Now,

⟹

2

1

m

2

v

2

2

=100

⟹

2

1

×2m×(

2

v

1

2

)=100

⟹

2

1

m

1

v

1

2

=100×

2

1

×4=200J

So, Total Kinetic Energy =300J

Answer 2

Answer:

Let mass of pieces are m1=m and m2=2m

Applying conservation of momentum.

m1v1=m2v2⇒mv1=2mv2⇒v1=2v2

Now,

⇒12m2v22=100⇒12×2m×(v12)2=100⇒12m1v12=100×12×4=200 J

Total KE = 300 J

Explanation:

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