Question

A stationary sound wave has frequency 165 hz speed of sound in air is 330m/s then the distance between 2 consecutive nodes is

Answer 1

Given that,

Frequency of sound wave is 165 Hz

Speed of sound in air is 330 m/s

To find,

The distance between 2 consecutive nodes.

Solution,

We know that the distance between two consecutive nodes is $\dfrac{\lambda}{2}$. Using the formula of speed of a wave. So,

$v=f\lambda\\\\v=f\dfrac{\lambda}{2}\\\\330=\dfrac{165\times \lambda}{2}\\\\\lambda=\dfrac{330}{2\cdot165}\\\\\lambda=1\ m$

So, the distance between 2 consecutive nodes is 1 m.

Learn more,

Nodes

https://brainly.in/question/10608408

Answer 2

Answer:

1m

Explanation:

firstly Let us calculate the normal wavelength as:

v=f l (here l is lambda or wavelength)

l=330÷165

l=2m

Now for measuring the distance between two consecutive nodes we know that d= l÷2

d=2÷2

d=1m

hence the distance between two consecutive nodes would be 1m.