Question

A stationary wave is setup on a string of length 10 cm. Four loops are formed. what is the distance between two consecutive crests?

A) 4.5 cm B) 5 cm C) 2.5 cm D) 1.25 cm

PLS DON'T SPAM. EXPLAIN STEP BY STEP. THANKS​

Answer 1

Answer:

The answer is B)2.5cm

Explanation:

Loops of stationary waves consists of nodes and antinodes .The distance between two consective antinodes(crest) or nodes(trough) is equal to 1 wavelenght , same is the case with two consecutive crest or trough so when 10cm the total lenght is divided on n=4 (given) than one wavelenght comes out which is 2.5 cm .

Answer 2

Given:

A stationary wave is setup on a string of length 10 cm. Four loops are formed.

To find:

Distance between consecutive crests?

Calculation:

• Since a stationary wave with 4 loops is formed, the crests would be analogous to antinodes.

• Distance between consecutive antinodes is $\lambda/2$.

In this case :

$4 \times \dfrac{ \lambda}{2} = L$

$\implies \: \dfrac{ \lambda}{2} = \dfrac{L}{4}$

$\implies \: req. \: distance = \dfrac{10}{4}$

$\implies \: req. \: distance = 2.5 \: cm$

So, distance between consecutive crests is 2.5 cm