A stationary wheel starts rotating about its own axis at constant angular acceleration.If it completes 50 rotation on 2s then the number of rotation made by it in the next two seconds
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θ=12αt2
2π×10=12α(3)2
2πn=12α(6)2
n- total number of rotation in 6 seconds
n10=369
n=40
the number of rotations in the first 3 second is 10. therefore the number of rotations in the next 3 seconds is
∴n1+n2=n=40
n2=40−10=30
2π×10=12α(3)2
2πn=12α(6)2
n- total number of rotation in 6 seconds
n10=369
n=40
the number of rotations in the first 3 second is 10. therefore the number of rotations in the next 3 seconds is
∴n1+n2=n=40
n2=40−10=30
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