A statue is being carved by a sculptor. The original piece of marble weights 140 kg on the first week 35% is cut away.on the second week sculptor chips of 26 kg and on the third week he chips of two fifth of the remainder and he completed the statue weight of final statue in kg is
Answers
Initial weight of a marble used to build a statue=140 kg
Percentage of the marble that was cut away on the first week=35%
Weight of the marble on the first week:-
Thus, the weight of the statue's marble in the first week=91 Kg
Weight of marble chips that were cut from the statue's marble during the second week=26 Kg
Weight of the statue's marble during the second week:-
Thus, the weight of the statue's marble during the second week=65 Kg
Part of the marble statue that was cut away during the third week is:-
Which means :-
Weight of the marble statue during the third week:-
Thus, the weight of the statue on the third week=39 Kg
Therefore, the weight of the final staue=39 Kg
Given : A statue is being carved by a sculptor. The original piece of marble weighs 140 kg. On the first week 35% is cut away. On the second week the sculptor chips off 26 kg and on the third week he chips off two-fifths of the remainder
To Find : Weight of the final statue (in kg) is
Solution:
Initial Weight = 140 kg
On the first week 35% is cut away.
Cut away = (35/100)140 = 49 kg
Remaining = 140 - 49 = 91 kg
On the second week the sculptor chips off 26 kg
Remaining 91 - 26 = 65 kg
on the third week he chips off two-fifths of the remainder
= (2/5) 65
= 26 kg
Remaining Weight = 65 - 26
= 39 kg
Weight of the final statue (in kg) is 39
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