Science, asked by souparnak5917, 11 months ago

A steady current is passed for 30 minutes through two voltameters connected in series:a copper voltameter [Cu cathode in CuSO4 solution], and a silver voltameter [Ag cathode in AgNO3 solution]. If the mass of copper deposited in the first voltameter is 21.17 g; calculate the mass of silver deposited on the cathode in the other voltameter. Given: Relative Atomic mass of Cu = 63.5, Ag = 108.0.

Answers

Answered by Durgeshsinghrajpu
3
According to Faraday’s first law of electrolysis the amount of metal deposited on the cathode m = Zit. Where Z is electro chemical equivalence (e.c.e) of a metal, I is the current passed through the voltameter and t is the time for which the current is passed through the electrolyte. Use the Formula m - Zit and substitute the values in it after converting all the units in to one measuring system.
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