A steady current is passed for 30minutes through two voltmeters connected in series: a copper voltmeter [Cu cathode in copper sulphate solution], and a silver voltmeter [Ag cathode in silver nitrate solution]. If the mass of copper deposited in the first voltammeter is 21.17g, Calculate the mass of silver deposited on the cathode in the other voltammeter. Given relative atomic mass of Cu = 63.5 and Ag = 108.
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M = ZIT
Z = M/IT
Z = 21.17/63.5×30×60sec
Z = 0.0002
M = ZIT
M = 0.0002×108×30×60
M = 36.936 is your answer
Z = M/IT
Z = 21.17/63.5×30×60sec
Z = 0.0002
M = ZIT
M = 0.0002×108×30×60
M = 36.936 is your answer
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