Question

A steady current of 1 ampere flows through a conductor. Calculate the number of electrons that flows through any section of the conductor in 1 second. (Charge on electron 1.6 X 10-19 coulomb).​

Answer 1

Answer:

Hey mate

current (i) = (number (n)× charge on electron (e))÷time

therefore i = ne ÷ t

by putting the value

1 = n × 1.6×10^-19 ÷1

n = 1 ÷ 1.6× 10^-19

n = 0.625×10^19

» n = 6.25 × 10^18

¡.e

» n = 6 × 10^18

hence,number of electrons that flow through any section of conductor in 1 second with 1 A current is 6 × 10^18

Answer 2

$\huge\underline\mathtt\red{Given}$

A steady current of 1 ampere flows through a conductor. Calculate the number of electrons that flows through any section of the conductor in 1 second. (Charge on electron 1.6 X 10-19 coulomb).

$\huge\underline\mathtt\red{ToFind}$

The number of electrons?

$\rule{300}{2}$

Current (Q) = 1 ampere.

Time(t) =1 second.

$\huge\underline\mathtt\red{FormulaUsed}$

$I = \frac{Q}{t}$

Here,

I = Strength of current

Q=Amount of charges flowing

t=Time in second unit

$\huge\underline\mathtt\red{Calculation}$

$I = ne \div 1$

Now,by putting the values,we get,

$\sf{1 = n \times 1.6 \times {10}^{ - 19} \div 1}$

$\sf{n = 1 \div 1.6 \times {10}^{ - 19} }$

$\sf{n = 0.65 \times {10}^{ - 19} }$

$\rule{300}{2}$

$\huge\underline\mathtt\red{ThankYou}$

The amount of positive charge that flows through any cross-section of a conductor in every second is called the strength of current in that conductor.

Strength of current is a scalar quantity, although it has direction.

Dimension of current strength =[ I ].

Unit of strength of current:

CGS unit of current strength is emu(Electromagnetic unit) and its SI unit is Ampere (A).

If through any cross-section of a conductor 1 columb of charge flows for 1 second, then the strength of current through that conductor is said to be 1 ampere (A).

$\underline{\boxed{\mathtt{\green{1 \: emu \: of \: current \: strength \: = 10A}}}}$