Physics, asked by Rudranil420, 8 months ago

A steady current of 1 ampere flows through a conductor. Calculate the number of electrons that flows through any section of the conductor in 1 second. (Charge on electron 1.6 X 10-19 coulomb).​

Answers

Answered by Anonymous
16

Given:-

{\tt{\pink{\: Current (Q)\: = 1\: ampere}}}

{\tt{\pink{\:Time(t) = 1s}}}

To Find:-

The number of electrons .

Formula:-

Q = ne

Where,

Q = Amount of charge present in charged body.

n = whole number

e = charge of an electron.

Calculation:-

{\tt{ I = ne ÷ t }} \\    \\

{\tt{\red{\: Now ,\: putting \: the \: value, \: we\: get,}}}  \\    \\

{\implies{\tt{1 = n × 1.6 × 10{^-19} ÷ 1}}} \\    \\

{\implies{\tt{ n = 1  ÷ 1.6 × 10{^-19}}}} \\    \\

{\implies{\tt{n  =  0.625 × 10{^19} }}} \\    \\

Answered by ItsTogepi
8

\huge\underline\mathtt\red{Given}

A steady current of 1 ampere flows through a conductor. Calculate the number of electrons that flows through any section of the conductor in 1 second. (Charge on electron 1.6 X 10-19 coulomb).

\huge\underline\mathtt\red{ToFind}

The number of electrons?

\rule{300}{2}

  • Current (Q) = 1 ampere.
  • Time(t) =1 second.

\huge\underline\mathtt\red{FormulaUsed}

I =  \frac{Q}{t}

Here,

I = Strength of current

Q=Amount of charges flowing

t=Time in second unit

\huge\underline\mathtt\red{Calculation}

I = ne \div 1

Now,by putting the values,we get,

\sf{1 = n \times 1.6 \times  {10}^{ - 19}  \div 1}

\sf{n = 1 \div 1.6 \times  {10}^{ - 19} }

\sf{n = 0.65 \times  {10}^{ - 19} }

\rule{300}{2}

\huge\underline\mathtt\red{ThankYou}

The amount of positive charge that flows through any cross-section of a conductor in every second is called the strength of current in that conductor.

Strength of current is a scalar quantity, although it has direction.

Dimension of current strength =[ I ].

Unit of strength of current:

CGS unit of current strength is emu(Electromagnetic unit) and its SI unit is Ampere (A).

If through any cross-section of a conductor 1 columb of charge flows for 1 second, then the strength of current through that conductor is said to be 1 ampere (A).

\underline{\boxed{\mathtt{\green{1 \: emu \: of \: current \: strength \:  = 10</strong><strong>A</strong><strong>}}}}

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