Question

A steady current of 1 ampere flows through a conductor. calculate the number of electrons that flows through any section of the conductor in 1second

Answer 1

current (i) = (number (n)× charge on electron (e))÷time

therefore i = ne ÷ t
by putting the value
1 = n × 1.6×10^-19 ÷1
n = 1 ÷ 1.6× 10^-19
n = 0.625×10^19

Answer 2

Given: Current(I) = 1A

Time(t) = 1s

To Find: Number of electrons flowing through the conductor in 1 second

Solution:

We know that current is given as

I = q / t, where I is current, q is the charge and t is the time for which the charge flows.

1 = q / 1

q = 1 Coulomb

The charge is given as

q = ne, where q is the charge, n is the number of electrons and e is the charge on one electron.

The charge on one electron is 1.6 x 10 ⁻¹⁹C

1 = n x  1.6 x 10 ⁻¹⁹

n = 1/  1.6 x 10 ⁻¹⁹

n = 6.25 x 10 ¹⁸

Therefore, the number of electrons passing through a conductor carrying a current of 1 Ampere in 1 second are 6.25 x 10 ¹⁸.