Question

a steady flow, the velocities at points A and B. which were 100 cm apart, were 3 m/s and 6 m/s
respectively. If the velocity varies linearly between A and B, then what would be the convective
acceleration at В?
(A) 18 m/ s²
(B) 9 m/s²
(C) 12 m/s²
(D) None of the above​

Answer 1

Option (D). None of the above, is the answer.

Step-by-step explanation:

Velocity (u) at point A = 3 meter per second

Velocity (v) at point B = 6 meter per second

Distance between A and B = 100 cm = 1 meter

From the formula,

v² = u² + 2aΔx

Where v = velocity at point B

u = velocity at point A

a = acceleration

Δx = distance traveled

6² = 3² + 2a(1)

36 = 9 + 2a

a = $\frac{36-9}{2}$

a = 13.5 meter per second square

Therefore, Option D. None of the above will be the answer.

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Answer 2

Answer:

A

Step-by-step explanation:

convective acceleration = vdv/ds

At point B, v= 6m/s

convective acceleration = 6*((6-3)/1) = 18m/s2