Question

A steal wire of length 4cm and radius 2.5mm is stretch by force of 50N find out increase in the length if the young modulus is 2.4×10^7N/m^2

Answer 1

Answer:

its steel not steal

Explanation:

Answer 2

Answer:

Here, l=4.0m;Δl=2×10

−3

m;a=2.0×10

−6

m

2

,Y=2.0×10

11

N/m

2

(i) The energy density of stretched wire

u=

2

1

× stress × strain

=

2

1

×Y×(strain)

2

=

2

1

×2.0×10

11

×(2×10

−3

)/4)

2

=0.25×10

5

=2.5×10

4

J/m

3

.

(ii) Elastic potential energy = energy density × volume

=2.5×10

4

×(2.0×10

−6

)×4.0J=20×10

−2

=0.20J.

Answer ByavatarToppr

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