a steam engine has an efficiency of 20%.It is given and energy of 1000 cal/min, what is actual work done by it in joules and in calories
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Answers
Answered by
28
Explanation:
n=output power/inputpower ×100
20=(x/1000)×100
x=200cal/min
P=w/t
200=w/1
w=200j
Answered by
11
Explanation:
let the total amount of energy be x
efficiency of the steam engine = 20%
efficient energy = 1000 calories
ATQ
20%of x= 1000
20/100*x=1000
x=1000*100/20= 5000 calories
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