A steam engine of mass 3 * 104 kg pulls two wagons
each of mass 2 x 104 kg with an acceleration of
0.2 m s-2 Neglecting functional forces, calculates then (i) force exerted by the engine. (ii) force experienced
by each wagon.
Answers
Answer:
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Answer:
Explanation:
Solution :-
Given :-
Mass of the engine engine, m₁ = 3 × 10⁴ kg
Mass of each wagon, m₂ = 2 × 10⁴ kg
Acceleration, a = 0.2 m/s²
To Calculate :-
Force exerted by the engine
Force experienced by each wagon
Formula to be used :-
F = ma
When force exerted by the engine is to be calculated,
m = m₁ + 2m₂
(Total mass (m) = mass of the engine + mass of two wagons)
F = ma
= [(3 × 10⁴) + 2(2 × 10⁴)] × 0.2
= (3 × 10⁴ + 4 × 10⁴ × 0.2
F = 1.4 × N
In the second case, we will only take the mass of one wagon.
F = ma
= 2 × 10⁴ × 0.2
force exerted by the engine = 0.4 × 10⁴ N.
force experienced by each wagon=2*10^4*1/5 (using f=ma) =4*10^3
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